sábado, 11 de diciembre de 2010

SULFUR GROUP


SULPHUR GROUP.

SULPHUR.

ALLOTROPIC FORMS OF SULPHUR.

Contrary to oxygen whose atoms form diatomic molecules with double bonds, tendency of sulphur to build a double bond with another atom of sulphur is less than tendency oxygen atoms have.
The most stable form is S8. Hybridization of atoms in this molecule is sp3, and there are simple bonds between atoms of sulphur. There are rhombic form and monoclinic form of S8 molecule, both yellow substances.

Stability of S8 is higher than stability of S6. Let us see these picture of S8 and S6.
To obtain it:

HCl  +  Na2S2O3  =  S6  +  NaCl  +  H2O
                      t = -10ºC

S6 is dissolved in benzene, and we will obtain S6 evaporating the solvent.
Sn: The molecule is a chains of atoms of sulphur bonded by the disappeared electrons which are in the terminal atoms.

Sulphur in solid state.

The most stable allotropic form of sulphur in solid state is rhombic form S8. It is not soluble in H2O. The solubility of S8 in C6H6, alcohols and ethers.  The solubility is high in CS2.

Sulphur in liquid state.

When we change the temperature, the increase of temperature produces changes of colors and viscosity, because of the changing of molecular structures.

 There are different allotropic forms: S8, Sn, and S4. We can separate them attending to the different solubility they have in CS2.
 The polymerization heat is nearly 0 because when there is a increase of temperature, the number of broken bonds and the number of built bonds are nearly the same.
 The increase of viscosity is because the synthesis of chains of atoms of sulphur.

Sulphur in vapor state.

 We can find molecules of S8, S4 and S2. When temperature is high, the percentage of simple molecules as S2 is bigger. If we cool the vapor to obtain, we can obtain  molecules of S4 in solid state. It is a diamagnetic molecule and it will be a purple solid. To get a fast cooling, we will need liquid nitrogen.

SELENIUM.

ALLOTROPIC FORMS OF SELENIUM

 Red selenium: It is soluble in organic solvents. This solutions does not conduct electricity. The stability of this allotropic form is not very high, so red selenium converts in grey selenium very slowly. In this process, heat is produced.
 Grey selenium is hexagonal, has metallic aspect, it is fragile and you can not solve it in organic solvents.

Liquid selenium is red brown.
Vapor selenium is yellow.

 Electricity conductivity in selenium is low, but when temperature is high, conductivity is bigger, so we can say that selenium is a semiconductor (semimetal). Increase in electricity could be very big (1000 times) when we light selenium, so it is perfect for building photoelectric cells.

TELLURIUM.

 We do not know molecules that form cycles in tellurium. It seems silver, because tellurium has the same bright. It has characteristic typical of no metallic, for example, you can obtain dust from tellurium.
 Vapor tellurium is yellow.
Te2 is a paramagnetic molecule.

IONS OF ELEMENTS OF SULPHUR GROUP.

 The trend to form negative ions decreases when atomic number increases (S, Se, Te).
When we go down in the group (S, Se, Te), the size of negative ions increases so polarizability will be higher and ionic character in the molecule decreases when we go down the group.

 In aqueous solution, anions are bases.

S2-  +  H2O  =  HS1-  +  HO1-
HS1-  H2O  =  H2S  +  HO1-

Positive ions: We can find cations which have a cycle structure as:

S82+      Se82+      Te82+

The distance between atoms number 3 and 7 is bigger than the distance in a pure covalent bond, but that distance is not so big, so we can think that there is an one kind interaction between those atoms.

Position number 1’ is only for S82+. Position 1 is for Se82+ and Te82+.
To explain all we have just said, we have to think that this group of atoms are a big ion, so we can think that atoms number 3 and 7 have lost one electron, so both atoms have one single electron and we can think in a interaction between spins of two electrons.

 Talking about tellurium, despite of not forming any structure, ion of tellurium form a cycle structure.

There are also bivalent cations of 4 atoms with a flat structure. The ion is like a square.
To obtain these ions we have to mix the melted halide with the element and aluminum chloride.

Te   +   TeCl4   +   AlCl3   =   2 Te4+   +   AlCl41-


CHEMICAL PROPERTIES.

 Sulphur and selenium reacts directly with hydrogen producing hydrogen sulphide and hydrogen selenide.
Contrary to we have just explained, we can not obtain H2Te using as reactives tellurium and hydrogen. Stability of hydrades decreases when the atomic mass of the atom which is bonded with hydrogen  increases.

 Sulphur, selenium and tellurium react with halogens producing halides , and they also react with metals producing binary salts.

 As oxidizing elements, its oxidizing capacity decreases when we go down the group, in fact we can not consider selenium as an oxidizing reactive.

HOW TO OBTAIN.

 We can obtain sulphur in the nature (cheap method).
 To obtain big quantities of sulphur, we produce this chemical reaction in industry:

2 H2S   +   O2   ->   2 H2O   +   S         ΔH<0
                         Fe2O3.

We can also obtain sulfur by reduction of sulfur dioxide that is produced in roasting process to obtain metals oxide from metals sulfur.

SO2   +   C   ->   CO2   +   S

We can obtain selenium by chemical reduction of selenium dioxide we obtain in lead rooms in the industry of sulfuric acid.

 We can find tellurium in minerals that contain gold and silver.

 Polonium appears in radioactivity process. To obtain 0.03 grams of polonium, we have to work with 103 tons pitchblende.

WE CAN USE SULFUR AND SELLENIUM FOR:

 We will use sulfur for: Fumigation, synthesis of sulfuric acid, synthesis of carbon disulfide, rubber vulcanization, to produce powder.

 We use selenium for making photoelectric cells, and to make ruby glass.

viernes, 19 de noviembre de 2010

OXYGEN


OXYGEN.

INTRO

Let us study oxygen. It is a very different element if we compare it with the rest of its group, sulphur, selenium of tellurium. Intermolecular interactions are very weak so ebullioscopy temperature is very low. The solubility in water is also very low.
Oxygen molecule is paramagnetic and the bond coefficient will be two.
The electronic configuration is:
1s2 2s2 2p4
So the molecular orbital diagram is:

OZONE
If there is only atomic oxygen, there are two possibilities:
O  +  O  =  O2             ΔH1
O  +  O2  =  O3           ΔH2
ΔH1  <  ΔH2.
Attending to a thermodynamic point of view, the first chemical reaction is produced, but this is not true because the probability of the second reaction is higher because the kinetic of the first reaction is very low.
 But finally, ozone transforms in oxygen.
2 O3  =  3O2.
 The structure of ozone is angular. Attending to the electronic configuration of oxygen atom, the molecular diagram orbital could be:

IONS OF OXYGEN.

The only element whose electro negativity is higher than oxygen is fluorine. Ionization energy is very high, so we can think that O21+ does not exist, but we can see that oxygen can lose one electron, increasing its bond coefficient to two point five.

PtF6  +  O2  ->  O2+[PtF6]1-.
                 t = 600ºC

O2- is formed in two steps:

a.-   O  +  e-  =  O1-;      ΔH < 0
b.-   O1-  +  e-  =  O2-;      ΔH > 0

Let us analyze the endothermic process. We could think O1- is more stable than O2-, but a compensation with the reticular energy of the compound formed is produced in O2-, so finally this ion is more stable. It forms part of many ionic compounds, and its polarizing power is low, so the contribution of covalent bond in the compound is very low; we can say they are ionic compounds.

 O2- in water is a Broensted base.

O2-  +  H2O  ->  2HO1-

The molecule of the ion O22- is similar to the molecule of F2. The bond coefficient is 1, and it is a diamagnetic molecule.

CHEMICAL PROPERTIES.

Let us study direct chemical reactions. Oxygen forms covalent compounds with no metals. Oxygen forms compounds with a high percentage of ionic bond. It will depend the oxidation state of the metal; if the oxidation state is high (more than three), the polarization power of the metal will be high, so the percentage of covalent bond will increase. We can see Cr and Mn, that can form anions like:

CrO42-, MnO41-.

It is curious that reactivity of oxygen with carbon, sulphure, hydrogen, is very high, but in environmental temperature, oxygen does not react with this compounds. But if we give energy to start the process, the reaction will be exothermic and the kinetic of the reaction will be high. They can be violent reactions.
 Let us study reactions in water. Oxygen is a very good oxidant agent. It makes higher the oxidation state of the metals.

Fe2+  -  e-  ->  Fe3+.

Sometimes, we can find exothermic reactions where the metal loses one electron, but the activation energy required is very big so finally the chemical reaction is not possible.

 Silver, loses one electron with the light.

Ag1+  ->  Ag2+

AgO is formed in AgNO3 solutions (with the light).

HOW TO OBTAIN OXYGEN.

 Distillation can be used to separate air into oxygen and nitrogen. We liquefy the air cooling it to -100ºC. We heat the liquid air, and when temperature is -96ºC. it will stop despite of keeping on heating, because nitrogen will change from liquid to gas. When temperature started to climb, only oxygen and another compounds will be in liquid state (in a proportion of 1%). When temperature is at -73ºC, temperature will stop again and oxygen will change from liquid to gas, so we can save it in cylinders to high pressure.

 We can separate oxygen and hydrogen from water through electrolysis.

WE CAN USE OXYGEN FOR:

-To prepare SO3 to synthesize sulphuric acid. The compound will reacts with oxygen will be SO2.
-To synthesize NO using NH3 to prepare HNO3.
-To medical uses.

viernes, 12 de noviembre de 2010

HOW TO OBTAIN HALOGENS


HOW TO OBTAIN HALOGENS
 Fluorine, chlorine and bromine  are in the nature as ions in salts, so we can oxide the ions to obtain the halogens.
2 X1- -1e-   ->   X2.
Let us study one by one:
-Fluorine: It is the strongest element, so which element is going to oxide anion fluorine? There is not any element can do it, so we will use an electrolytic method using electricity. But what liquid will we use to dissolve the salt? If we use water, O2- of the water will be oxide instead of F1-.  We will have to dissolve the salt of fluorine in a solution formed by KF dissolved in HF.
 -Chlorine: We will use an electrolytic method using a concentrated solution of NaCl in water. The cathode is made of iron and the anode is made of graphite. Let us study the chemical reaction produced in both electrodes.
Cathode (oxidation, it is not a galvanic cell, it is an electrolytic cube):
2 Cl1-  -  2 e-  ->  Cl2.
Anode:
Na1+ + HO1-  ->  NaOH
2 H1+  + e-  ->  H2.
-Bromine: We will obtain bromine using bromides (salts) from the water in the sea. The oxidant agent will be chlorine molecule.
2 Br1-  +  Cl2  ->  Br2  +  2 Cl1-.
-Iodine: We will obtain iodine using “Chile Nitrate”, NaIO3, using acids.
IO31-  +  SO2  ->  SO42-  +  I1-
IO31-  +  I1-  ->  I2  +  H2O

HALOGENS ARE USED FOR...
-Fluorine: to synthesize freons for freezers, Teflon, to rich uranium (UF6), to make firebombs (IF3), in water for drinking to avoid problems in teeth, caries problems (NaF).
-Chlorine: In water to avoid infections microorganisms (bacters). As bleach substances.
-Bromine: Bromide anions are used as sedative substances, it is also used to produce tears, and in photographs.
-Iodine: In ethanol, it is used to avoid infections in injuries.
It is also used to calculate the oxygen dissolved in water.
First of all we mix MnSO4 and Mn(OH)2
Later we add KI, and finally we empty some ml of concentrated H2SO4
Thanks to these reagents, ones we put H2SO4, each oxygen is inside water, one Iodide anion converts to iodine. So finally, we only have to know I2 using Na2S2O3 using starch to know the final point of the reaction.

lunes, 8 de noviembre de 2010

CHEMICAL PROPERTIES OF HALOGENS.

Let us study ions of halogens. Electronic affinity is not very high in fluorine as it is supposed. It is because of the high electronic repulsion which is higher than in other halogens as chlorine of bromine, because of the little size of fluorine atom.
 Ions of halogens form typical ionic compounds when they bond with alkali metals and with alkaline metals.
When we solve this compounds in water, they have ion dipole interaction with water molecules.
 Let us study chemical properties of halogens.

CHEMICAL PROPERTIES OF HALOGENS.
Let us study direct chemical reactions. Reactivity falls from fluorine to iodine. The high reactivity of fluorine molecule is because of its low dissociation energy. In fact, fluorine molecule reacts violently with hydrogen in low temperature, fluorine reacts directly with metals in exothermic reactions and platinum and gold are attacked by fluorine.
Chlorine is not as reactive as fluorine. It reacts with all the no metals except carbon, nitrogen and oxygen. So if we want to obtains compounds with this elements and chlorine, we will have to work with indirect chemical reactions.
Talking about the reactivity of chlorines with metals, we have to say that chlorine reacts with alkali metals, with alkaline metals, and with aluminum very easy (velocity of reaction is high). To combine chlorine with transition metals, we have to heat.
 Dry chlorine is very inert, so it is perfect to transport chorine inside receptacles made of iron.
Activity of bromine and iodine is very low.
Percentage of covalent bond grow up from fluorine ion to iodine ion because of polarizability of halogen is bigger when atomic volume is bigger.
Let us study reactions in water.
Halogens are oxidants but its oxidant power decrease from fluorine to chlorine. If we talk about fluorine and chlorine, its oxidizing power, in low values of pH, is bigger than oxidizing power oxygen has.
X2 + H2O = 2 X1- + 2 H1+ + ½ O2.
Attending to a thermodynamic point of view, bromine and iodine have to react in the same way as fluorine and chlorine, but the kinetic of the reaction is slow.
Talking about oxidizing power halogens have, fluorine oxides to chlorine, chlorine oxides to bromine, and so and so.
2 Br1- +  Cl2 = Br2 + 2 Cl1-.
2 I1- +  Br2 = I2 + 2 Br1-.
Chlorine does not oxide permanganate (oxidizing powerful of permanganate is bigger), so it is a good method to obtain chlorine.
Cl1- + MnO41- -> Mn2+ + Cl2.

viernes, 5 de noviembre de 2010

SOLUBILITY OF HALOGENS


 Talking about solubility of this compounds in water, fluorine reacts with water violently. We can explain the high reactivity of fluorine attending to the law value of its dissociation energy. If we draw the molecular orbitals diagram of the molecule of fluorine, we notice that there are two not bonding p orbitals with 4 electrons. The repulsion force created by these electrons could be the reason of the low dissociation energy.

As we can see, fluorine is a diamagnetic molecule with a bond coefficient one
 Chlorine dissolves in water, and in fact chlorine reacts with water but not as fluorine does.
The solubility of bromine and iodine is low, but it could be better if we add KBr or KI.
 Finally, the solubility of iodine is high in carbon tetrachloride and in carbon disulphide. In the first compound the solution is purple. Iodine can also solve in ethanol and the color of these solutions is red. Iodine can be absorbed by starch, and the solution turns to purple

Acústico en el pasado mes de Agosto

Primera de las 6 partes del ensayo acústico que hice en Agosto a la espera de la incorporación del nuevo batería del grupo (FLACUCHOS: Julián, bajo; Manolo, guitarra, y yo la otra guitarra y voz).http://www.youtube.com/watch?v=XYRAVxkUKJk
Aquí os dejo una foto del grupo:

HALOGENS
(Tthe place where I work)

Molecules of fluorine, chlorine, bromine and iodine and diatomic molecules. Astatine is synthesized artificially and it only exist in traces.
Intermolecular interactions are very weak in diatomic molecules of halogens, so fluorine molecule is a gas whose color is closer to green. It is very difficult to obtain the liquid. Talking about chlorine molecule, we can say that it is a yellow gas. We can obtain it liquid in high pressure. Bromine molecules is a red liquid, and iodine molecule is a black solid; It seems a metal and iodine sublimes, so we can get the vapor directly from the solid state.
 We can explain the color thinking that going down the group of halogens, the number of orbitals is higher and the difference between the levels of energy is less, so transits of electrons from one level to another is easier.